(25z^2-10z+4)/125

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Solution for (25z^2-10z+4)/125 equation: 


z in (-oo:+oo)

(25*z^2-(10*z)+4)/125 = 0

(25*z^2-10*z+4)/125 = 0

25*z^2-10*z+4 = 0

25*z^2-10*z+4 = 0

DELTA = (-10)^2-(4*4*25)

DELTA = -300

DELTA < 0

1 = 0

1/125 = 0

z belongs to the empty set

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